Estimation and Costing MCQ Quiz - Objective Question with Answer for Estimation and Costing - Download Free PDF

Last updated on May 14, 2025

Latest Estimation and Costing MCQ Objective Questions

Estimation and Costing Question 1:

What is the primary scope of the National Electric Code (NEC) 2011?

  1. To focus exclusively on renewable energy systems
  2. To define standards for power generation and transmission only
  3. To provide guidelines for the design and installation of electrical systems to ensure safety and reliability
  4. To regulate the manufacturing of electrical appliances and devices

Answer (Detailed Solution Below)

Option 3 : To provide guidelines for the design and installation of electrical systems to ensure safety and reliability

Estimation and Costing Question 1 Detailed Solution

The correct answer is option 3.

National Electric Code (NEC) 2011

The primary scope of the National Electrical Code (NEC) 2011 is to provide a set of guidelines for the safe installation and use of electrical wiring and equipment. It focuses on minimizing hazards and preventing accidents, injuries, and fires related to electrical installations. 

Safety: The NEC prioritizes safety by outlining general safety procedures, providing recommendations for safe practices, and addressing specific hazards. 

Electrical Installations: The code applies to various types of electrical installations, including those in buildings, industrial sites, and even outdoor locations. 

Equipment and Wiring: The NEC covers the selection, installation, and maintenance of electrical equipment and wiring, ensuring they meet safety standards. 

Hazardous Areas: The code includes provisions for special precautions in areas with explosive or otherwise dangerous atmospheres. 

Estimation and Costing Question 2:

Which of the following is a critical factor in the installation and estimation of agricultural pumps and flourmills?

  1. Ignoring the load characteristics to simplify the design
  2. Focusing only on the mechanical components of the system 
  3. Ensuring the system operates without any protective devices
  4. Calculating the power requirements and selecting appropriate protective devices

Answer (Detailed Solution Below)

Option 4 : Calculating the power requirements and selecting appropriate protective devices

Estimation and Costing Question 2 Detailed Solution

The correct answer is option 4.

This is indeed the correct and most critical factor because:

  • Accurate power calculation ensures the system is appropriately sized and avoids overload. Protective devices (like circuit breakers, fuses, overload relays) are essential to prevent equipment damage and ensure safety.
  • Power calculations ensure the motor, cables, and supply system are appropriately sized.

Estimation and Costing Question 3:

What is a key factor in the installation and costing of electrical systems for commercial buildings?

  1. Ignoring safety standards to reduce costs
  2. Ensuring compliance with electrical codes and standards while estimating materials and labour costs 
  3. Focusing only on decorative lighting and aesthetics
  4. Eliminating the use of protective devices

Answer (Detailed Solution Below)

Option 2 : Ensuring compliance with electrical codes and standards while estimating materials and labour costs 

Estimation and Costing Question 3 Detailed Solution

The correct answer is option 2.

Compliance with electrical codes (like NEC, IEC) and safety standards is crucial in any commercial electrical installation. It ensures:

  • Safety of occupants and maintenance personnel.
  • Legal compliance to avoid penalties, rework, or shutdowns.
  • Accurate costing, since estimates include only approved materials and proper labor practices.
  • System reliability reduces the chance of electrical faults or fire.


Ignoring these codes can result in failed inspections, costly legal consequences, or dangerous systems.

Estimation and Costing Question 4:

Which of the following best describes the role of cogeneration in energy conservation and how the application of a tariff system can help reduce energy bills?

  1. Cogeneration is only applicable in large industrial settings and has no impact on energy conservation, while tariff systems are solely used for revenue generation by utilities. 
  2. Cogeneration and tariff systems are unrelated concepts, and neither contributes to energy conservation or cost reduction.
  3. Cogeneration increases energy consumption by producing excess electricity, and tariff systems are used to penalize high energy users without reducing bills.
  4.  Cogeneration reduces energy waste by simultaneously producing electricity and useful thermal energy, while a welldesigned tariff system incentivizes off-peak energy usage, lowering overall costs. 

Answer (Detailed Solution Below)

Option 4 :  Cogeneration reduces energy waste by simultaneously producing electricity and useful thermal energy, while a welldesigned tariff system incentivizes off-peak energy usage, lowering overall costs. 

Estimation and Costing Question 4 Detailed Solution

The correct answer is option 4.

Cogeneration

  • Cogeneration (also called Combined Heat and Power, CHP) is a highly efficient process that uses one fuel source (e.g., natural gas) to generate electricity and heat.
  • Cogeneration reduces energy waste by simultaneously producing electricity and useful thermal energy, while a well-designed tariff system incentivizes off-peak energy usage, lowering overall costs.
  • This results in higher overall efficiency (up to 80–90%) compared to just 30–50% in conventional separate generation.


Tariff system

  • A tariff system is a pricing structure for electricity use (e.g., flat rate, time-of-use, or demand-based).
  • Tariff systems that are well-designed (like time-of-use pricing) encourage energy consumption during off-peak hours, leading to lower energy bills and better load distribution.

Estimation and Costing Question 5:

What is the first step in the design procedure for electrical installations in commercial buildings?

  1. Conducting a load analysis to determine power requirements
  2. Installing protective devices without planning
  3. Selecting decorative lighting fixtures
  4. Ignoring safety standards to reduce costs

Answer (Detailed Solution Below)

Option 1 : Conducting a load analysis to determine power requirements

Estimation and Costing Question 5 Detailed Solution

The correct answer is option 1.

In the design procedure for electrical installations in commercial buildings, the first step must be understanding how much power the building will need. This involves:

  • Estimating electrical loads: Lighting, HVAC, elevators, office equipment, etc.
  • Calculating peak demand: Helps size transformers, panels, and feeders correctly.
  • Planning for future expansion: Ensures flexibility without major redesign.


Only after this analysis can an engineer begin selecting conductor sizes, designing protective systems, specifying panel boards, switchgear, and layout. Without a load analysis, you risk installing an unsafe or non-functional system. It can lead to power outages, fire hazards, or legal violations.

Top Estimation and Costing MCQ Objective Questions

The cheap and temporary system of internal wiring is?

  1. Conduit wiring
  2. Cleat wiring
  3. CTS or TRS wiring
  4. Casing-capping

Answer (Detailed Solution Below)

Option 2 : Cleat wiring

Estimation and Costing Question 6 Detailed Solution

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The cheapest system of wiring is cleat wiring.

Type of Wiring

Name of Wiring

Application

Temporary

Flexible wire

Decoration purpose in marriages, exhibitions, fairs, used for extension of temporary connections in various buildings

Temporary

Cleat wiring

Used for temporary wiring in small places, shops and residential buildings for a period of not more than one year

Permanent

Casing Capping

Used for the light and fan in the shops and houses

Permanent

Batten wiring

Used in shops, halls, houses and other big buildings

Permanent

PVC wiring

Used in damp places and where the wiring is necessary required to be water and fire proof

Permanent

Conduit pipe wiring

Used in godowns, cinema halls, workshops and industries

Permanent

Concealed wiring

Used in hospitals, drawing rooms, high precision workshops etc.

The type earthing suitable for sandy areas is

  1. Horizontal strip earthing
  2. Rod
  3. Plate
  4. Pipe

Answer (Detailed Solution Below)

Option 2 : Rod

Estimation and Costing Question 7 Detailed Solution

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  1. Horizontal strip earthing: This type of earthing is used at places which have rocky earth bed.
  2. Rod earthing: This system of earthing is suitable for areas which are sandy in character. This system of earthing is very cheap as no excavation work is involved.
  3. Plate earthing: It is used for larger stations and transmission lines, where the fault current, likely to be high.
  4. Pipe earthing: It is used for ordinary soil or dry and rocky soil. The size of the pipe depends upon the current to be carried and the type of the soil. Usually, the pipe used for this purpose is of diameter 38 mm and 2.5 meters in length for ordinary soil or of greater length in case of dry and rocky soil.

_____ earthing is the best form of earthing and is very cheap in cost.

  1. Rod
  2. Plate
  3. Pipe
  4. strip

Answer (Detailed Solution Below)

Option 3 : Pipe

Estimation and Costing Question 8 Detailed Solution

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  • Pipe earthing is the most common and best system of earthing as compared to other systems suitable for the same earth and moisture conditions.
  • Pipe earthing is the best form of earthing and is very cheap in cost.
  • In this method the galvanized steel and perforated pipe of approved length and diameter in place upright in permanently wet soil.
  • The size of the pipe depends upon the current to be carried and the type of soil.

_________ is the money put down in addition to the tender.

  1. True money
  2. Exploit money
  3. Earnest money
  4. Deposit money

Answer (Detailed Solution Below)

Option 3 : Earnest money

Estimation and Costing Question 9 Detailed Solution

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The correct answer is option 3.

​Earnest money deposit

  • It is a small refundable fee collected by the department from each bidder to ensure that a bidder does not submit a dummy bid or back out at the time of tender opening.
  • It is returned when all the bids are opened & tender is awarded to another firm.
  • It is generally 2% of the tender value.

Security deposit

  • It is the amount of money that has to be deposited with the buyer once the tender is awarded to a bidder to ensure that if he does not complete the task as per the work order, the buyer can recover the loss by forfeiting his security deposit.
  • It can be in the form of a demand draft or bank guarantee.
  • When the contractor completes the project, he gets its security deposit returned.
  • It is generally 10% of the tender value.

Additional Information Caution money:

  • It is the amount of money that someone has to pay when they rent property, use a service, etc. which will not be refunded if they damage something or owe money at the end of their contract.

Bank guarantee:

  • It is a written contract given by a bank on behalf of a customer that undertakes to pay or discharge the liability of the debtor in case of any default.

What should be the minimum clearing distance (in feet) between the equipment for the 750 to 1000 kV line? 

  1. 20
  2. 25
  3. 45
  4. 50

Answer (Detailed Solution Below)

Option 3 : 45

Estimation and Costing Question 10 Detailed Solution

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The minimum clearing distance between the equipment for the 750 to 1000 kV line must be 45 feet.

The minimum clearing distance that equipment should keep from the power lines of different voltage levels is:

Voltage Level

Distance (in feet)

Up to 50 kV

10

50 to 200 kV

15

200 to 350 kV

20

350 to 500 kV

25

500 to 750 kV

35

750 kV to 1000 kV

45

Over 1000 kV

50

What should be the minimum depth of trench from the ground level for cables carrying a voltage between 3.3 kV and 11 kV?

  1. 0.9 m
  2. 0.45 m
  3. 1.0 m
  4. 1.05 m

Answer (Detailed Solution Below)

Option 1 : 0.9 m

Estimation and Costing Question 11 Detailed Solution

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The desired minimum depth of laying from the ground surface to the top of the cable is as follows:

High voltage cables (3.3 kV to 11 kV rating) = 0.9 m

High voltage cables (22 kV, 33 kV rating) = 1.05 m

Low voltage and control cables = 0.75 m

Cables at road crossings = 1.00 m

If the wiring in a building as a 2.4-kW load, what will be the permissible insulation resistance to earth for a 240-V system of supply?

  1. 0.08 MΩ
  2. 0.05 MΩ
  3. 0.02 MΩ
  4. 0.12 MΩ

Answer (Detailed Solution Below)

Option 4 : 0.12 MΩ

Estimation and Costing Question 12 Detailed Solution

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Concept:

Full Load Current(IFL): A full load current is a maximum current that electrical equipment is designed to carry under rated conditions.

Leakage current(Ilek)A leakage current is an electric current in an unwanted conductive path under normal operating conditions.

Note: According to IE Rule 48 The maximum permissible value of leakage current should not be exceeded beyond the \(\frac{1}{{5000}} \)times of full load current.

Insulation Resistance(IR): An insulation resistance (IR) is the total resistance between any two points separated by electrical insulation.

It is given by,

\(IR = \frac{{Supply\;Voltage}}{{{I_{lekage}}}}\)

Note: IR of a cable is also given as:

\(IR = \frac{\rho }{{2\pi l}}{\log _e}\frac{{{r_2}}}{{{r_1}\;}}\)

Where ρ is the resistivity of cable on Ωm

l is the length of cable in the metre.

ris the radius of core in metre

ris the radius of cable in metre

Calculation:

Given, P = 2.4 kW, V = 240 V

IFL = 2400 / 240 = 10 A

According to IE Rule 48:

\({I_{lek}} = \frac{{{I_{FL}}}}{{5000}} = \frac{{10}}{{5000}} = 0.002\;A\)

\(IR = \frac{{supply\;voltage}}{{{I_{lekage}}}} = \frac{{240}}{{0.002}} = 120,000 = 0.12\;M{\rm{\Omega }}\)

Select the correct option for the given figure.

F1 Shubham Shraddha 17.08.21 D51

  1. Current transformer (CT)
  2. Power transformer - two winding
  3. Voltage transformer or Potential transformer (PT)
  4. Three winding transformer

Answer (Detailed Solution Below)

Option 4 : Three winding transformer

Estimation and Costing Question 13 Detailed Solution

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The symbol of different Transformer is shown below:

Three Winding Transformer

Current Transformer

Step Down Transformer

Step Up Transformer

Ferrite Core Transformer

Iron Core Transformer

Variable Transformer

Air-Core Transformer

Auto Transformer

F1 Shubham Shraddha 17.08.21 D46

What does the given figure represent?

  1. Single circuit two ground wire tower
  2. Two-bundle conductor two-ground wire tower
  3. Single and double circuit towers with one ground wire
  4. HVDC bipolar tower

Answer (Detailed Solution Below)

Option 1 : Single circuit two ground wire tower

Estimation and Costing Question 14 Detailed Solution

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Different Type of Tower Design:

1. Three Phase Single circuit two ground wire Tower:

F1 Shubham Shraddha 17.08.21 D46

2. Three Phase Single circuit one ground wire Tower:

F1 Nakshtra 19-08-21 Savita D2

2. Double Three Phase Single circuit one ground wire Tower:

F1 Nakshtra 19-08-21 Savita D3

4. HVDC Bipolar Tower:

F1 Nakshtra 19-08-21 Savita D4

For specific wiring in a building, the full load current is 7.5 A. what will be the permissible insulation resistance to earth for a 240 V system of supply?

  1. 0.20 MΩ
  2. 0.18 MΩ
  3. 0.16 MΩ
  4. 0.22 MΩ

Answer (Detailed Solution Below)

Option 3 : 0.16 MΩ

Estimation and Costing Question 15 Detailed Solution

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Concept:

Full Load Current(IFL): A full load current is a maximum current that electrical equipment is designed to carry under rated conditions.

Leakage current(Ilek): A leakage current is an electric current in an unwanted conductive path under normal operating conditions.

Note: According to IE Rule 48 The maximum permissible value of leakage current should not be exceeded beyond the \(\frac{1}{{5000}} \)times of full load current.

Insulation Resistance(IR): An insulation resistance (IR) is the total resistance between any two points separated by electrical insulation.

It is given by,

\(IR = \frac{{Supply\;Voltage}}{{{I_{lekage}}}}\)

Note: IR of a cable is also given as:

\(IR = \frac{\rho }{{2\pi l}}{\log _e}\frac{{{r_2}}}{{{r_1}\;}}\)

Where ρ is the resistivity of cable on Ωm

l is the length of cable in the metre.

ris the radius of core in metre

ris the radius of cable in metre

Calculation:

Given, IFL = 7.5 A

According to IE Rule 48:

\({I_{lek}} = \frac{{{I_{FL}}}}{{5000}} = \frac{{7.5}}{{5000}} = 0.0015\;A\)

\(IR = \frac{{supply\;voltage}}{{{I_{lekage}}}} = \frac{{240}}{{0.0015}} = 160,\;000 = 0.16\;M{\rm{\Omega }}\)

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