Data Interpretation MCQ Quiz - Objective Question with Answer for Data Interpretation - Download Free PDF
Last updated on Jul 4, 2025
Latest Data Interpretation MCQ Objective Questions
Data Interpretation Question 1:
Comprehension:
Directions: Read the following table carefully and answer the following questions:
Number of candidates selected in competitive examinations in different commissions like SSC, UPSC, IBPS, and RRB over the given years
|
Commission→ |
SSC |
UPSC |
IBPS |
RRB |
| Years ↓ | ||||
|
2016 |
700 |
860 |
540 |
465 |
|
2017 |
580 |
400 |
795 |
655 |
|
2018 |
785 |
655 |
450 |
785 |
|
2019 |
675 |
415 |
800 |
845 |
Which commission has selected the lowest number of candidates from 2016 to 2019.
Answer (Detailed Solution Below)
Data Interpretation Question 1 Detailed Solution
Calculations:
Total number of candidates selected in SSC from 2016 to 2019 is
⇒ 700 + 580 + 785 + 675
⇒ 2,740
Total number of candidates selected in UPSC from 2016 to 2019 is
⇒ 860 + 400 + 655 + 415
⇒ 2,330
Total number of candidates selected in IBPS from 2016 to 2019 is
⇒ 540 + 795 + 450 + 800
⇒ 2,585
Total number of candidates selected in RRB from 2016 to 2019 is
⇒ 465 + 655 + 785 + 845
⇒ 2,750
So, The lowest number of candidates selected in UPSC from 2016 to 2019 is 2,330
∴ UPSC commission has selected the lowest number of candidates from 2016 to 2019
Data Interpretation Question 2:
Comprehension:
Directions: Read the following table carefully and answer the following questions:
Number of candidates selected in competitive examinations in different commissions like SSC, UPSC, IBPS, and RRB over the given years
|
Commission→ |
SSC |
UPSC |
IBPS |
RRB |
| Years ↓ | ||||
|
2016 |
700 |
860 |
540 |
465 |
|
2017 |
580 |
400 |
795 |
655 |
|
2018 |
785 |
655 |
450 |
785 |
|
2019 |
675 |
415 |
800 |
845 |
Find the difference between the sum of the selected candidates in IBPS in 2018 and 2019 and the sum of the selected candidates in RRB in 2016 and 2017.
Answer (Detailed Solution Below)
Data Interpretation Question 2 Detailed Solution
Calculations:
According to the question, we have
The sum of the selected candidates in IBPS in 2018 and 2019 is
⇒ 450 + 800
⇒ 1,250
The sum of the selected candidates in RRB in 2016 and 2018 is
⇒ 465 + 655
⇒ 1,120
Difference is
⇒ 1,250 – 1,120
⇒ 130
∴ The difference between the sum of the selected candidates in IBPS in 2018 and 2019 and the sum of the selected candidates in RRB in 2016 and 2017 is 130.
Data Interpretation Question 3:
Comprehension:
Directions: Read the following table carefully and answer the following questions:
Number of candidates selected in competitive examinations in different commissions like SSC, UPSC, IBPS, and RRB over the given years
|
Commission→ |
SSC |
UPSC |
IBPS |
RRB |
| Years ↓ | ||||
|
2016 |
700 |
860 |
540 |
465 |
|
2017 |
580 |
400 |
795 |
655 |
|
2018 |
785 |
655 |
450 |
785 |
|
2019 |
675 |
415 |
800 |
845 |
Find the ratio of the sum of the candidates selected in SSC exam in 2016 and 2017 to the sum of the candidates selected in IBPS exam in 2018 and 2019.
Answer (Detailed Solution Below)
128 : 125
Data Interpretation Question 3 Detailed Solution
Calculations:
According to the question, we have
The total number of candidates selected in the SSC exam in 2016 and 2017 is
⇒ 700 + 580
⇒ 1280
The total number of candidates selected in the IBPS exam in 2018 and 2019 is
⇒ 450 + 800
⇒ 1250
So, The Ratio of the sum of the candidates selected in the SSC exam in 2016 and 2017 to the sum of the candidates selected in the IBPS exam in 2018 and 2019 is
⇒ 1280 : 1250
⇒ 128 : 125
∴ The Ratio of the sum of the candidates selected in SSC exam in 2016 and 2017 to the sum of the candidates selected in IBPS exam in 2018 and 2019 is 128 : 125.
Data Interpretation Question 4:
Comprehension:
Directions: Read the following table carefully and answer the following questions:
Number of candidates selected in competitive examinations in different commissions like SSC, UPSC, IBPS, and RRB over the given years
|
Commission→ |
SSC |
UPSC |
IBPS |
RRB |
| Years ↓ | ||||
|
2016 |
700 |
860 |
540 |
465 |
|
2017 |
580 |
400 |
795 |
655 |
|
2018 |
785 |
655 |
450 |
785 |
|
2019 |
675 |
415 |
800 |
845 |
Find out the SSC selected candidates in 2017 is how much percentage more than the UPSC selected candidates in 2017.
Answer (Detailed Solution Below)
Data Interpretation Question 4 Detailed Solution
Formula used:
Percentage more = (Difference/Given) × 100
Calculations:
The difference between the selected candidates in SSC and UPSC exam in 2017 is
⇒ 580 – 400
⇒ 180
Percentage more = (Difference/Given) × 100
⇒ (180/400) × 100
⇒ 0.45 × 100
⇒ 45%
∴ The SSC selected candidates in 2017 is 45% more than the UPSC selected candidates in 2017.
Data Interpretation Question 5:
Comprehension:
Directions: Read the following table carefully and answer the following questions:
Number of candidates selected in competitive examinations in different commissions like SSC, UPSC, IBPS, and RRB over the given years
|
Commission→ |
SSC |
UPSC |
IBPS |
RRB |
| Years ↓ | ||||
|
2016 |
700 |
860 |
540 |
465 |
|
2017 |
580 |
400 |
795 |
655 |
|
2018 |
785 |
655 |
450 |
785 |
|
2019 |
675 |
415 |
800 |
845 |
Find out the average of the RRB selected candidates from 2016 to 2019.
Answer (Detailed Solution Below)
Data Interpretation Question 5 Detailed Solution
Formula used:
Average = Sum of total observations/Number of given observations
Calculations:
According to the question, we have
Total number of candidates selected in RRB exam in 2016, 2017, 2018, 2019
⇒ 465 + 655 + 785 + 845
⇒ 2,750
The average of the RRB selected candidates is
⇒ 2,750/4
⇒ 687.5
∴ The average of the RRB selected candidates from 2016 to 2019 is 687.5
Top Data Interpretation MCQ Objective Questions
Comprehension:
Given below the data about three employees of a call center named ZINTOCA. In the given table, data about calls received by them, calls selected for further lead and calls finally received is given:
| A | B | C | |
| Initial calls(% out of total calls) | 40% | 30% | 30% |
| Lead calls (% out of initial calls) | 80% | x% | 88% |
| Final received calls(% out of lead calls) | 90% | 80% | y% |
Total number of initial calls in the company is 24000 and total number of calls not received by company C is 4464 less than the total number of calls received by company A. Find the value of y.
Answer (Detailed Solution Below)
Data Interpretation Question 6 Detailed Solution
Download Solution PDFCalculation:
Let the total number of calls be 1000z.
Initial calls (% out of total calls) of A = (1000z × 40/100) = 400z
Initial calls (% out of total calls) of B = (1000z × 30/100) = 300z
Initial calls (% out of total calls) of C = (1000z × 30/100) = 300z
Lead calls (% out of initial calls) of A = (400z × 80/100) = 320z
Lead calls (% out of initial calls) of B = (300z × x/100) = 3zx
Lead calls (% out of initial calls) of C = (300z × 88/100) = 264z
Final received calls (% out of lead calls) of A = (320z × 90/100) = 288z
Final received calls (% out of lead calls) of B = (3zx × 80/100) = 3zx × (4/5)
Final received calls (% out of lead calls) of C = (264z × y/100)
Total number of initial calls in the company = 24000
⇒ (400z + 300z + 300z) = 24000
⇒ 1000z = 24000
⇒ z = (24000/1000)
⇒ z = 24
Total number of calls not received calls by C = (300h – 264z × y/100)
⇒ (300 × 24 – 264z × y/100)
⇒ (7200 – 264z × y/100)
According to the question
Total number of calls not received by company C is 4464 less than the total number of calls received by company A
⇒ (7200 – 264z × y/100) + 4464 = 288z
⇒ (7200 – 264 × 24 × y/100) + 4464 = 288 × 24
⇒ 7200 – 6336y/100 + 4464 = 6912
⇒ (720000 – 6336y + 446400)/100 = 6912
⇒ (720000 – 6336y + 446400) = 6912 × 100
⇒ (1166400 – 6336y) = 691200
⇒ (-6336y) = (691200 – 1166400)
⇒ (-6336y) = -475200
⇒ y = [-475200/(-6336)]
⇒ y = 75
∴ The value of y is 75
The table shows the daily income (in Rs.) of 50 persons.
Study the table and answer the question:
|
Income (Rs) |
No. of persons |
|
Less than 200 |
12 |
|
Less than 250 |
26 |
|
Less than 300 |
34 |
|
Less than 350 |
40 |
|
Less than 400 |
50 |
How many persons earn Rs. 200 or more but less than Rs. 300?
Answer (Detailed Solution Below)
Data Interpretation Question 7 Detailed Solution
Download Solution PDFCalculation:
Number less than 200 = 12
Number less than 250 = 26
Number less than between 250 and 200 = (26 – 12)
⇒ 14
Again,
Number less than 250 = 26
Number less than 300 = 34
Number less than between 300 and 250 = (34 – 26)
⇒ 8
Persons earn Rs. 200 or more but less than Rs. 300 = (14 + 8)
⇒ 22
∴ Required persons is 22
Various expenditures incurred by a publishing company for publishing a book in 2018 are given in the following pie chart. Study the chart and answer the question.
Price printed on a book is 15% above the cost price. If the price printed on a book is Rs. 942, then the cost of paper for a single copy in Rs. is (rounded off to one decimal place)
Answer (Detailed Solution Below)
Data Interpretation Question 8 Detailed Solution
Download Solution PDFCalculation:
Let the Cost price of the book be 100
Then, Marked Price of the book is 100 + (15% of 100) = 115
Printed price or marked price = 942
Cost price of book = 942 × (100/115)
⇒ 819.13
Now,
Paper cost = 819.13 × 15/100
⇒ 122.869 ≈ 122.9
∴ The required answer is Rs. 122.9
Study the given pie-chart carefully and answer the following question. If scholarship has to be paid out of the donation fund, then what is the percentage of donation fund used for this purpose (rounded off to two decimal places)?
The entire fund that school gets from different sources is equal to Rs. 10 lakh
Answer (Detailed Solution Below)
Data Interpretation Question 9 Detailed Solution
Download Solution PDFCalculation:
Total fund got by school = 100% = 1000000
Funds got through donation = 35%
Scholarship paid = 26%
Required percentage = 26/35 × 100
⇒ 2600/35 = 74.285% ≈ 74.29%
∴ The correct answer is 74.29%.
The given data shows the registration of bikes and total vehicles (in thousands) for 6 months in 2017 in City X.
Note: In the chart, the first number represents bikes and the second number represents total vehicles.
Based on the given data, the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 is _______.
Answer (Detailed Solution Below)
Data Interpretation Question 10 Detailed Solution
Download Solution PDFNumber of registration of vehicles other than bikes in January 2017 = 27,000 - 21,000 = 6,000
Number of registration of vehicles other than bikes in April 2017 = 35,000 - 20,000 = 15,000
∴ the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 = 15,000 - 6,000 = 9,000
Directions: The data for family sizes in a town is given below. Based on the bar graph, answer the question given below:
Calculate the average family size from the given data.
Answer (Detailed Solution Below)
Data Interpretation Question 11 Detailed Solution
Download Solution PDFCalculation:
Number of families having 1 member = 5
Total members = 5
Number of families having 2 members = 30
Total members = 60
Number of families having 3 members = 45
Total members = 135
Number of families having 4 members = 40
Total members = 160
Number of families having 5 members = 25
Total members = 125
Number of families having 6 members = 5
Total members = 30
So, the total membes in all types of families = 5 + 60 + 135 + 160 + 125 + 30 = 515
Total number of families = 5 + 30 + 45 + 40 + 25 + 5 =150
The average family size = 515 / 150 = 3.4
Hence, option 3 is correct.
Study the given table and answer the question that follows.
The table shows the classification of 100 students based on the marks obtained by them in History and Geography in an examination.
|
Subject |
Marks out of 50 |
||||
|
40 and above |
30 and above |
20 and above |
10 and above |
0 and above |
|
|
History |
9 |
32 |
80 |
92 |
100 |
|
Geography |
4 |
21 |
66 |
81 |
100 |
|
Average (Aggregate) |
7 |
27 |
73 |
87 |
100 |
Based on the table, what is the number of students scoring less than 20% marks in aggregate?
Answer (Detailed Solution Below)
Data Interpretation Question 12 Detailed Solution
Download Solution PDFCalculation
We have 20% of 50 = 10
Therefore Required number:
Number of students scoring less than 10 marks in aggregate
= 100 - Number of students scoring 10 and above marks in aggregate
= 100 - 87
= 13.
The number of students scoring less than 20% marks in aggregate is 13.
The line chart given below shows the profit percentage of a company on 5 different products P1, P2, P3, P4 and P5.
The expenditure of product P5 is Rs. 46000. What is the revenue of product P5?
Answer (Detailed Solution Below)
Data Interpretation Question 13 Detailed Solution
Download Solution PDFGIVEN:
From the chart
Profit percentage in P5 = 8%
Expenditure = Rs. 46000
FORMULA USED:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
CALCULATION:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
⇒ 8 = [(Revenue – 46000)/46000] × 100
⇒ Revenue – 46000 = 8 × 460
⇒ Revenue = 3680 + 46000
⇒ Revenue = 49680The following table shows the number of different items in different shops and their respective selling prices per unit.
|
Shops |
Total No. of Items |
AC ∶ Cooler ∶ Fan |
Selling Price per unit |
||
|
Cooler |
AC |
Fan |
|||
|
A |
5000 |
4 ∶ 5 ∶ 1 |
8000 |
25000 |
8500 |
|
B |
1800 |
3 ∶ 2 ∶ 4 |
10000 |
20000 |
16000 |
|
C |
3400 |
6 ∶ 4 ∶ 7 |
6000 |
42000 |
15000 |
|
D |
3600 |
4 ∶ 2 ∶ 3 |
12000 |
32000 |
8000 |
|
E |
4000 |
5 ∶ 1 ∶ 4 |
8000 |
26500 |
12200 |
|
F |
1210 |
2 ∶ 4 ∶ 5 |
11000 |
28000 |
11100 |
Find the percentage of total revenue which comes from Cooler from shop E, considering all given items are being sold from shop E and from all the given shops only given three items are being sold. (Rounded off to three decimal places)
Answer (Detailed Solution Below)
Data Interpretation Question 14 Detailed Solution
Download Solution PDFCalculation:
Total cooler sold by shop E = 4000 × (1/10)
⇒ 400
Selling price of 400 coolers = 400 × 8000
⇒ 3200000
Total ACs sold by shop E = 4000 × (5/10)
⇒ 2000
Selling price of 2000 ACs = 2000 × 26500
⇒ 53000000
Total Fans sold by shop E = 4000 × (4/10)
⇒ 1600
Selling price of 1600 Fans = 1600 × 12200
⇒ 19520000
Now,
Required % = [3200000/(3200000 + 53000000 + 19520000)] × 100
⇒ [3200000/(75720000)] × 100
⇒ 4.226 ≈ 4.23%
∴ The required answer is 4.23%.
study the given table and answer the question that follows.
The table shows the classification of 100 students based on the marks obtained by them in Statistics and Mathematics in an examination out of 50.
| Subject | 40 and above | 30 and above | 20 and above | 10 and above | 0 and above |
| Mathematics | 8 | 33 | 90 | 92 | 100 |
| Statistics | 5 | 22 | 60 | 87 | 100 |
If at least 60% marks in Mathematics are required for pursuing higher studies in Mathematics, then how many students will be eligible to pursue higher studies in Mathematics?
Answer (Detailed Solution Below)
Data Interpretation Question 15 Detailed Solution
Download Solution PDFCalculation:
Total marks = 50
Eligible for higher studies in mathematics marks = 50 × 60% = 30
Total students who are eligible to pursue higher studies in mathematics = 33
∴ The correct answer is 33.