Question
Download Solution PDFA और B एक साथ किसी कार्य को 20 दिनों में पूरा कर सकते हैं जबकि B और C मिलकर इसे 24 दिनों में पूरा कर सकते हैं। यदि A, C से दोगुना कुशल है, तब B अकेले उसी कार्य का 40% कितने समय में करेगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
A = 2C
A + B कार्य 20 दिनों में करते हैं।
B + C कार्य 24 दिनों में करते हैं।
प्रयुक्त अवधारणा:
कुल कार्य = कार्य करने में लिए गये समय का लघुत्तम समापवर्तक
गणना:
20 और 24 का लघुत्तम समापवर्तक 120 है
इसलिए, A और B की दक्षता = 120/20 = 6 तथा B और C की दक्षता = 120/24 = 5
अब 2C + B = 6 और B + C = 5
इसलिए, C = 1
B = 4
कार्य का 40% = 120 × 2/5 = 48 इकाई
इसलिए, B समय लेगा = 48/4 = 12 दिन
∴ B अकेले उसी कार्य का 40% भाग 12 दिनों में पूरा करेगा।
Shortcut Trick
अब 2C + B = 6 और B + C = 5
इसलिए, C = 1
B = 4
इसलिए,
A, B और C = 2, 4 और 1
कार्य का 40% = 120 × 2/5 = 48 इकाइयाँ
इसलिए, B को 48/4 = 12 दिन लगेंगे।
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