10.5 सेमी उंचीच्या समच्छिन्न शंकुच्या दोन गोलाकार बाजूंची त्रिज्या अनुक्रमे 5 सेमी आणि 3 सेमी आहेत.  (π = 22/7) सेमी3मध्ये त्याचे घनफळ किती आहे?

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SSC CGL Previous Paper 59 (Held On: 12 June 2019 Shift 2)
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  1. 539
  2. 545
  3. 564
  4. 552

Answer (Detailed Solution Below)

Option 1 : 539
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समच्छिन्न शंकुच्या दोन गोलाकार चेहऱ्यांची त्रिज्या 5 सेमी आणि 3 सेमी आहेत

शंकूच्या गोलाकारसमच्छिन्न शंकुची उंची H = 10.5 सेमी

जस आपल्याला माहित आहे,

समच्छिन्न शंकुचे घनफळ = 1/3 × π [R 2 + r 2 + Rr] H

⇒ 1/3 × 22/7 × [52 + 32 + 5 × 3] × 10.5

⇒ 11 × [25 + 9 + 15]

⇒ 11 × 49

⇒ 539
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