The radii of two circular faces of the frustum of a cone of height 10.5 cm are 5 cm and 3 cm respectively. What is its volume in cm3 (π = 22/7)?

This question was previously asked in
SSC CGL Previous Paper 59 (Held On: 12 June 2019 Shift 2)
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  1. 539
  2. 545
  3. 564
  4. 552

Answer (Detailed Solution Below)

Option 1 : 539
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Detailed Solution

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Radii of two circular faces of the frustum of a cone are 5 cm and 3 cm

Height of the circular frustum of cone H = 10.5 cm

As we know,

Volume of the frustum of cone = 1/3 × π [R2 + r2 + Rr] H

⇒ 1/3 × 22/7 × [52 + 32 + 5 × 3] × 10.5

⇒ 11 × [25 + 9 + 15]

⇒ 11 × 49

⇒ 539
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