जर दोन बिंदू (5, 4) आणि (-3, k) मध्ये जोडणारी रेषा kx – y + 11 = 0 या रेषेशी समांतर असेल तर 'k' चे मूल्य किती आहे?

  1. 4/9
  2. 5/7
  3. 2/3
  4. 7/11

Answer (Detailed Solution Below)

Option 1 : 4/9
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Detailed Solution

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दोन बिंदू जोडणार्‍या रेषेचे समीकरण:

\(\left( {y - 4} \right) = \frac{{\left( {k - 4} \right)}}{{ - 3 - 5}} \times \left( {x - 5} \right)\)

वरील रेषेचा उतार = \(m1 = \frac{{4 - k}}{8}\)

आणखी एक रेषा:

kx - y + 11 = 0

y = kx + 11

वरील रेषेचा प्रवणता = k

दोन्ही रेषा समांतर आहेत.

m1 = m2

(4 – k)/8 = k

4 – k = 8k

4 = 9k

k = 4/9

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