Question
Download Solution PDFIn an election between two candidates, 10% of the voters in the voter list did not cast their vote, whereas 10% of the votes cast were found to be invalid. The winning candidate got 56% of the valid votes and won the election by a margin of 1,458 votes. What is the total number of voters enrolled in the voter list?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
10% of the voters did not cast their vote and 10% of the polled vote were found invalid.
The winning candidate got 56% of the valid votes and won the election by a margin of 1,458 votes.
Concept Used:
The percentage is calculated based on 100 i.e. 100 is the base
40% means 40 out of 100
Calculation:
Let, the total enrolled voters be x
10% did not cast a vote means cast or polled vote = 9x/10
10% vote is invalid
That means valid vote = (90/100) × (9x/10)
⇒ 81x/100
The winning candidate got 56% of the polled vote means the looser got (100 – 56) = 44% vote
Winer candidate got total {(56/100) × (81x/100)} vote
And the looser candidate got {(44/100) × (81x/100)} vote
Accordingly,
{(56/100) × (81x/100)} - {(44/100) × (81x/100)} = 1458
⇒ (81x/100) × {(56 – 44)/100} = 1458
⇒ (81 × 12)x/10000 = 1458
⇒ x = (1458× 10000)/(81 × 12)
⇒ x = 15000
∴ Total 15000 voters enrolled in the voter list.
Shortcut Trick
Total voters = 1458 × (100/90) × (100/90) × 100\(56 - 44) = 15000
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