Question
Download Solution PDFA scores 4 marks less than B, B got 12 marks less than passing marks. A’s marks is 80% of the passing marks. Find the marks scored by B.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A scores 4 marks less than B.
B got 12 marks less than passing marks.
A’s marks is 80% of the passing marks.
Formula used:
Let the passing marks be P.
Let the marks scored by B be B marks, and A’s marks will be A marks.
Calculation:
From the given information:
A = B - 4 (A scores 4 marks less than B)
B = P - 12 (B got 12 marks less than passing marks)
A = 0.8 × P (A’s marks is 80% of the passing marks)
Now substitute the value of A from the second equation into the third equation:
B - 4 = 0.8 × P
Substitute B = P - 12 into this equation:
(P - 12) - 4 = 0.8 × P
P - 16 = 0.8 × P
Now, solve for P:
P - 0.8P = 16
0.2P = 16
P = 16 / 0.2 = 80
The passing marks are 80. Now, substitute P = 80 into the equation for B’s marks:
B = P - 12 = 80 - 12 = 68
∴ The marks scored by B is 68.
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