A scores 4 marks less than B, B got 12 marks less than passing marks. A’s marks is 80% of the passing marks. Find the marks scored by B.

Given:

A scores 4 marks less than B.

B got 12 marks less than passing marks.

A’s marks is 80% of the passing marks.

Formula used:

Let the passing marks be P.

Let the marks scored by B be B marks, and A’s marks will be A marks.

Calculation:

From the given information:

A = B - 4 (A scores 4 marks less than B)

B = P - 12 (B got 12 marks less than passing marks)

A = 0.8 × P (A’s marks is 80% of the passing marks)

Now substitute the value of A from the second equation into the third equation:

B - 4 = 0.8 × P

Substitute B = P - 12 into this equation:

(P - 12) - 4 = 0.8 × P

P - 16 = 0.8 × P

Now, solve for P:

P - 0.8P = 16

0.2P = 16

P = 16 / 0.2 = 80

The passing marks are 80. Now, substitute P = 80 into the equation for B’s marks:

B = P - 12 = 80 - 12 = 68

∴ The marks scored by B is 68.