Question
Download Solution PDFसमीकरण x2 − 2x + 13 = 0 का विविक्तकर क्या है? यह भी निर्धारित करें कि इस समीकरण के कितने वास्तविक हल हैं।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
द्विघात समीकरण x2 - 2x + 13 = 0 है।
प्रयुक्त सूत्र:
एक द्विघात समीकरण ax2 + bx + c = 0 का विविक्तकर (D) इस प्रकार दिया गया है:
D = b2 - 4ac
जहाँ: a = x2 का गुणांक, b = x का गुणांक, और c = अचर पद
गणना:
यहाँ, a = 1, b = -2, c = 13
⇒ D = (-2)2 - 4 × 1 × 13
⇒ D = 4 - 52
⇒ D = -48
चूँकि, विविक्तकर (D) ऋणात्मक है, इसलिए द्विघात समीकरण के कोई वास्तविक मूल नहीं हैं।
∴ सही उत्तर विकल्प (2) है।
Last updated on Jul 17, 2025
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