एक समकोण त्रिभुज में एक न्यूनकोण x के लिए, यदि sin x = \(\frac{3}{7}\) है, तो cosx का मान ज्ञात कीजिए।

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SSC CGL 2023 Tier-I Official Paper (Held On: 26 Jul 2023 Shift 2)
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  1. \(\frac{2}{7}\)
  2. \(\frac{3}{4}\)
  3. \(\frac{1}{\sqrt3}\)
  4. \(\frac{2(\sqrt{10})}{7}\)

Answer (Detailed Solution Below)

Option 4 : \(\frac{2(\sqrt{10})}{7}\)
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दिया गया है:

एक समकोण त्रिभुज में एक न्यूनकोण x के लिए, यदि sin x = \(\frac{3}{7}\) है,

गणना:

अतः, लम्ब 3 इकाई और कर्ण 7 इकाई है।

इसलिए आधार है, √72 - 32 = √40 इकाई 

⇒ 2√10 इकाई 

जैसा कि हम जानते हैं, cosx = आधार/कर्ण

इसलिए, cosx= \(\frac{2(\sqrt{10})}{7}\)

सही विकल्प 4 है।

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