Question
Download Solution PDFयदि sin (a + b) = 1 और cos (a - b) = \(\frac{1}{2} \) है, है, तो a का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
sin(A + B) = 1 और cos(A - B) = 1/2
प्रयुक्त सूत्र:
sin90° = 1
cos60° = 1/2
गणना:
sin(A + B) = 1
⇒ sin(A + B) = sin90°
⇒ A + B = 90° ....(1)
पुनः,
cos(A – B) = 1/2
⇒ cos(A – B) = cos60°
⇒ A – B = 60° .....(2)
समीकरण (1) और (2) को जोड़ने पर, हमें मिलता है
⇒ A + B + A – B = (90° + 60°)
⇒ 2A = 150°
⇒ A = (150/2)
⇒ A = 75°
a का मान 75° है।
Last updated on Jun 13, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.