একটি বৃত্তে, জ্যা PQ এবং TS-কে বাড়ানো হলে তারা R বিন্দুতে মিলিত হয়। যদি RQ = 14.4 সেমি, PQ = 11.2 সেমি এবং SR = 12.8 সেমি হয়, তাহলে জ্যা TS-এর দৈর্ঘ্য কত হবে?

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SSC CGL Previous Paper 81 (Held On: 9 March 2020 Shift 2)
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  1. 18 সেমি
  2. 16 সেমি
  3. 14.2 সেমি
  4. 112.4 সেমি

Answer (Detailed Solution Below)

Option 2 : 16 সেমি
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গণনা:

F1 A.K 6.5.20 Pallavi D2

RP = RQ + PQ = 14.4 + 11.2 = 25.6

আমরা জানি,

RP × RQ = RT × RS

⇒ 25.6 × 14.4 = RT × 12.8

⇒ RT = 28.8 সেমি

এখন, TS = RT - RS = 28.8 - 12.8 = 16 সেমি।
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