ஒரு வட்டத்தில் R இல் சந்திக்கும் வகையில் PQ மற்றும் TS நாண்கள் உருவாக்கப்படுகின்றன, RQ = 14.4 cm, PQ = 11.2 cm, மற்றும் SR = 12.8 cm எனில் , பின்னர் நாண் TS இன் நீளம் என்ன ?

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SSC CGL Previous Paper 81 (Held On: 9 March 2020 Shift 2)
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  1. 18 செ.மீ
  2. 16 செ.மீ
  3. 14.2 செ.மீ
  4. 112.4 செ.மீ

Answer (Detailed Solution Below)

Option 2 : 16 செ.மீ
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Detailed Solution

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கணக்கீடு:

F1 A.K 6.5.20 Pallavi D2

RP = RQ + PQ = 14.4 + 11.2 = 25.6

நாம் அறிந்தபடி,

RP × RQ = RT × RS

⇒ 25.6 × 14.4 = RT × 12.8

⇒ RT = 28.8 செ.மீ

இப்போது, TS = RT - RS = 28.8 - 12.8 = 16 செ.மீ.
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