Question
Download Solution PDFযদি \(y + {{1} \over y} = 3\) হয়, তাহলে \({{1} \over y^3} + y^3 + 2 \) এর মান কত?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
\(y + {{1} \over y} = 3\)
অনুসৃত ধারণা:
(a + b)3 = a3 + b3 + 3ab(a + b)
গণনা:
\(y + {{1} \over y} = 3\)
⇒ \((y + {{1} \over y})^3 = 27\)
⇒ \(y^3 + {{1} \over y}^3 +3(y +\frac{1}{y})= 27\)
⇒ \(y^3 + {{1} \over y}^3 +3 \times 3= 27\)
⇒ \(y^3 + {{1} \over y}^3 +9= 27\)
⇒ \(y^3 + {{1} \over y}^3= 18\)
⇒ \({{1} \over y^3} + y^3 + 2 \) = 20
∴ নির্ণেয় উত্তর 20
Last updated on Jul 10, 2025
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