Question
Download Solution PDFत्रिकोणाचे क्षेत्रफळ ज्याचे शिरोबिंदू (2, 4), (-3, -1) आणि (5, 3) दिले आहेत:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
(x1 ,y1) = (2, 4),
(x2,y2) = (-3, -1)
(x3 ,y3)= (5, 3)
वापरलेले सूत्र:
त्रिकोणाचे क्षेत्रफळ = [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]/2
गणना:
त्रिकोणाचे क्षेत्रफळ = [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]/2
सूत्रातून मूल्ये वजा करून
⇒ [2(-1 – 3) + (-3)(3 – 4) + 5(4 + 1)]/2
⇒ [-8 + 3 + 25]/2 = 10 चौरस एकके
Last updated on Jul 5, 2025
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