Question
Download Solution PDFजॉन 50 किमी/तास वेगाने 250 किमी अंतर पार करतो आणि नंतर तो 70 किमी/तास वेगाने 350 किमी अंतर पार करतो. संपूर्ण प्रवासासाठी त्याचा सरासरी वेग किमी/तास शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
जॉन 50 किमी/तास वेगाने 250 किमी अंतर पार करतो
तो 70 किमी/तास वेगाने 350 किमी अंतर पार करतो
वापरलेले सूत्र:
वेग = अंतर / वेळ
गणना:
⇒ पहिले अंतर कापण्यासाठी लागणारा वेळ = 250 / 50 = 5 तास
⇒ दुसरे अंतर कापण्यासाठी लागणारा वेळ = 350 / 70 = 5 तास
सरासरी वेग आहे
⇒ सरासरी वेग = (250 + 350) / (5 + 5) = 600 / 10 = 60 किमी/तास
⇒ त्यामुळे, त्याचा सरासरी वेग 60 किमी/तास आहे
Last updated on Jul 21, 2025
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