Question
Download Solution PDFΔDEF मध्ये, DE = 9 सेमी, EF = 12 सेमी आणि DF = 7 सेमी. जर DO हा ∠EDF चा कोन दुभाजक O वर EF ला भेटतो, तर OF ची लांबी शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
DE = 9 , EF = 12 सेमी, आणि DF = 7 सेमी
DO हा ∠EDF चा कोन दुभाजक आहे
वापरलेली संकल्पना:
त्रिकोणामध्ये, जर AD हा ∠BAC चा कोन दुभाजक असेल तर BC च्या विरुद्ध बाजूस D वर छेदतो.
कोन दुभाजक प्रमेयाद्वारे
AB/AC = BD/CD
गणना:
DE = 9 , EF = 12 सेमी, आणि DF = 7 सेमी
DO हा ∠EDF चा कोन दुभाजक आहे
कोन दुभाजक प्रमेयाद्वारे,
DE/DF = EO/OF
⇒ 9/7 = (EF - OF)/OF
⇒ 9/7 = (12 - OF)/OF
⇒ 9 x OF = 84 - 7 x OF
⇒ 16 x OF = 84
⇒ OF = 84/16
⇒ OF = 5.25 सेमी
∴ T हे OF चे मूल्य 5.25 सेमी आहे .
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