Question
Download Solution PDFजर गोलाचे घनफळ 24,416.64 सेमी3 असेल, तर त्याच्या पृष्ठभागाचे क्षेत्रफळ (π = 3.14 घ्या) दशांशाच्या दोन स्थानांपर्यंत शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
गोलाचे घनफळ 24,416.64 सेमी3 आहे
वापरलेली संकल्पना:
गोलाची घनफळ = 4/3πr3
गोलाचे पृष्ठभाग क्षेत्रफळ = 4πr2
येथे,
r = त्रिज्या
गणना:
4/3πr3 = 24416.64
⇒ r3 = 24416.64 × (3/4) × 1/3.14
⇒ r3 = 5832
⇒ r = 18
आता,
पृष्ठभाग क्षेत्रफळ = 4 × 3.14 × 182
⇒ 12.56 × 324
⇒ 4069.44 cm2
∴ पृष्ठभागाचे क्षेत्रफळ 4069.44 सेमी2 आहे.
Last updated on Jun 25, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.
->The UGC NET Exam Analysis 2025 for June 25 is out for Shift 1.