n संख्येला 6 ने भागल्यावर 3 उरते. तर (n2 + 5n + 8) ला 6 ने भागल्यावर उरलेली संख्या किती असेल?

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  4. 2

Answer (Detailed Solution Below)

Option 4 : 2
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वापरलेली संकल्पना:

युक्लिड्स डिव्हिजन लेमा, भाज्य = विभाजक (भागफल) + बाकी

गणना:

संख्या= n

तर, युक्लिड्स डिव्हिजन लेमानुसार

n= 6q+ 3  

तसेच, (n2 + 5n + 8) जेव्हा 6 ने भागल्यावर जी बाकी आहे, त्याला r म्हणा.

म्हणून, (n2 + 5n + 8)

(6q+3)2 + 5(6q+3) +8

36q2+ 9+ 36q+ 30q+ 15+ 8

36q2+ 66q+ 32

आता, वरील प्रत्येक अटींचा स्वतंत्रपणे विचार करा, जेव्हा त्यांना 6 ने विभाजित केले जाते तेव्हा उरलेली रक्कम किती असते.

36q2 ला 6 ने भाग जातो, म्हणून 6 ला 6 ने निःशेष भाग जातो. म्हणून, बाकी 0 आहे.

66q हा 6 ने भाग जातो कारण 66 ला 6 ने भाग जातो. म्हणून, बाकी 0 आहे.

32 ला 6 ने भागल्यावर बाकी 2 उरते.

म्हणून, (n2 + 5n + 8) साठी बाकी 2 आहे. 

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