दो लीटर तेल का वजन 16 N है। तेल के विशिष्ट घनत्व की गणना करें। जल का घनत्व 998 kg/m3 लीजिए।

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SSC JE Civil 15 Nov 2022 Shift 3 Official Paper
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  1. 0.846
  2. 0.786
  3. 0.856
  4. 0.816

Answer (Detailed Solution Below)

Option 4 : 0.816
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संकल्पना:

सापेक्ष घनत्व / विशिष्ट घनत्व =\(\frac{Density\;of\;fluid}{Density\;of\;standard\;fluid}\)  = \(\frac{ρ_f}{ρ_w}\)

द्रव का घनत्व = ρ = \(\frac{Weight}{Volume}\)

पानी का विशिष्ट घनत्व (मानक द्रव) 4 °C पर 1.0 है। 
गणना:

तेल का वजन =16N, तेल का आयतन =2L=\(0.002 m^3\),

पानी का घनत्व = ρw = 998 Kg/m3

तेल का घनत्व =\(\frac{Weight_{Oil}}{Volume_{Oil}}\)=\(\frac{16}{0.002}\)=8KN/m3

ρतेल =\(\frac{8000}{9.81}=815.49Kg/m^3\)

विशिष्ट घनत्व =\(\frac{ρ_{oil}}{ρ_w}\)\(\frac{815.49}{998}=0.816\)

G=0.816

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