दिखाए गए परिपथ में, यदि हम AA′ पर 1Ω के आंतरिक प्रतिरोध के साथ 2 वोल्ट के स्रोत को A′ पर धनात्मक टर्मिनल से जोड़ते हैं, तो R के माध्यम से धारा ___ होती है

F1 Raviranjan 13-1-22 Savita D16

This question was previously asked in
UKPSC JE Electrical 2013 Official Paper II (Held on 7 Nov 2015)
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  1. 2 A
  2. 1.66 A
  3. 1 A
  4. 0.625 A

Answer (Detailed Solution Below)

Option 4 : 0.625 A
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गणना:

F1 Raviranjan 13-1-22 Savita D16

जब स्रोत वोल्टेज लागू किया जाता है तो

F1 Reported Raviranjan 21-2-22 Savita 1

धारा स्रोत में स्रोत परिवर्तन लागू करना

F1 Raviranjan 13-1-22 Savita D18

नोडल विश्लेषण लागू करने पर

\(\rm \frac{V-1}{2}+\frac{V}{2}+\frac{V-2}{1}=0\)

या, \(\rm \frac{V-1+V+2V-4}{2}=0\)

या, 4 V = 5 ⇒ V = 1.25 V

\(\rm I=\frac{1.25}{2}=0.625\ A\)

अतः सही विकल्प (4) है।

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