यदि x + \(\rm \frac{1}{x}=8\) है, तो \(\rm \frac{5}{x^2-8x+2}\) का मान ज्ञात कीजिए।

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SSC CGL 2022 Tier-I Official Paper (Held On : 02 Dec 2022 Shift 4)
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  1. 3
  2. 4
  3. 0
  4. 5

Answer (Detailed Solution Below)

Option 4 : 5
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दिया गया है:

x + \(\rm \frac{1}{x}=8\)

गणना:

x + \(\rm \frac{1}{x}=8\)

⇒ x2 + 1 = 8x

⇒ x2 - 8x = - 1

अब,

\(\rm \frac{5}{x^2-8x+2}\) = \(\rm \frac{5}{-1\,+\,2}\)

⇒ 5

∴ अभीष्ट उत्तर 5 है।​

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