Question
Download Solution PDFयदि आकृति में खींचे गए त्रिभुज ABC में, AB = AC और ∠ACD = 130° है, तो ∠BAC किसके बराबर है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
AB = AC
∠ACD = 130°
प्रयुक्त अवधारणा:
रैखिक युग्म प्रमेय
कोण योग गुण = त्रिभुज के सभी कोणों का योग 180° होता है।
गणना:
त्रिभुज ABC में,
∠ACD + ∠ACB = 180° (रैखिक युग्म)
∠ACB = 180 - 130 = 50°
चूँकि, AB = AC,
त्रिभुज ABC एक समद्विबाहु त्रिभुज है।
∠ACB = ∠ABC = 50°
कोण योग गुण लागू करने पर,
∠ACB + ∠ABC + ∠BAC = 180°
∠BAC = 180 - (50 + 50)
∠BAC = 80°
∴ विकल्प 4 सही उत्तर है।
Last updated on Jul 10, 2025
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