एक विभाजन के दौरान, प्रांजल ने गलती से भाज्य के रूप में एक संख्या ले ली जो मूल भाज्य से 10% अधिक थी। उसने गलती से भाजक के रूप में एक ऐसी संख्या ले ली जो मूल भाजक से 25% अधिक थी। यदि मूल विभाजन प्रश्न का सही भागफल 25 था और शेषफल 0 था, तो यह मानते हुए कि उसकी गणना में कोई त्रुटि नहीं थी, प्रांजल ने कितना भागफल प्राप्त किया?

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SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 4)
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  1. 21.75
  2. 21.25
  3. 28.75
  4. 22

Answer (Detailed Solution Below)

Option 4 : 22
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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दिया गया है:

नया भाज्य = 110% × मूल भाज्य 

नया भाजक = 125% × मूल भाजक

प्रयुक्त सूत्र:

भाज्य = भाजक × भागफल + शेषफल

गणना:

माना मूल भाज्य = 100x

त्रुटि से वर्धित भाज्य = 100 ×110% = 110x

माना मूल भाजक = 100y

त्रुटि से वर्धित भाजक = 100y × 125% = 125y

भाज्य = भाजक × भागफल + शेषफल

100x = 100y × 25 + 0

x/y = 25/1

वर्धित भाज्य = 110x = 110 × 25 = 2750

वर्धित भाजक = 125y = 125 × 1 = 125

भागफल = 2750/125 = 22

∴ सही उत्तर 22 है।

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