एक 5 kVA परिणामित्र में 200 W की लौह हानि और 350 W की पूर्ण भार ताम्र हानि होती है। तो परिणामित्र में अधिकतम दक्षता तब होगी जब कुल हानि _________ होगी।

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SSC JE Electrical 15 Nov 2022 Shift 2 Official Paper
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  1. 300 W
  2. 200 W
  3. 275 W
  4. 400 W

Answer (Detailed Solution Below)

Option 4 : 400 W
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संकल्पना

परिणामित्र में कुल हानि निम्न है:

PT = लौह हानि + ताम्र हानि

अधिकतम दक्षता पर:

लौह हानि = ताम्र हानि

इस प्रकारPT = 2 × लौह हानि

Pc = (x)Pcufl

\(x=\sqrt{P_c\over P_{cufl}}\)

जहां, x = भारण का अंश

गणना

दिया गया​ है, लौह हानि = 200 W

अधिकतम दक्षता पर:

PT = 2 × 200

PT = 400 W

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