Question
Download Solution PDFA can finish a work in 15 days, B can finish the same work in 25 days. They work together for 5 days. The rest of the work is finished by A and C in 4 days. Then C alone can finish the work in:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A can finish in 15 days, B can finish it in 25 days.
They work together for 5 days.
Concept used:
Efficiency = (Total work / Total time taken)
Efficiency = work done in a single day
Calculation:
Let total work be 75 units ( LCM of 15 and 25 is 75)
The efficiency of A
⇒ 75 /15 = 5 units
The efficiency of B
⇒ 75 / 25 = 3 units
The efficiency of A+B,
⇒ (5 + 3) units = 8 units
In 5 days total work done is 8 × 5 = 40 units
Remaining work 75 - 40 = 35 units
In the last 4 days, A does 4 × 5 = 20 units
Remaining work 35 - 20 = 15 units done by C in 4 days
So C does 75 units in (75 / 15) × 4 = 20 days
∴ The correct option is 3
Last updated on May 28, 2025
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