Question
Download Solution PDFA body, starting from rest, falls from a building and reaches the ground in 2 secs. What will be the velocity of the body when it reaches the ground? (Acceleration due to gravity = 10 ms-2 )
This question was previously asked in
RRB Technician Grade III Official Paper (Held On: 30 Dec, 2024 Shift 1)
Answer (Detailed Solution Below)
Option 4 : 20 m/s
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General Science for All Railway Exams Mock Test
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Detailed Solution
Download Solution PDFThe correct answer is 20 m/s.
Key Points
- The body starts from rest, so the initial velocity (u) is 0 m/s.
- The time (t) taken to reach the ground is 2 seconds.
- The acceleration due to gravity (g) is 10 m/s².
- The final velocity (v) can be calculated using the formula v = u + gt.
- Substituting the values, v = 0 + (10 m/s² * 2 s) = 20 m/s.
Additional Information
- Acceleration due to Gravity (g):
- It is the acceleration that the Earth imparts to objects due to gravity.
- The standard value of g on Earth's surface is approximately 9.8 m/s², often rounded to 10 m/s² for simplicity in calculations.
- Free Fall:
- It is the motion of a body where gravity is the only force acting upon it.
- In a vacuum, all objects fall at the same rate regardless of their masses.
- Equations of Motion:
- These equations describe the relationship between displacement, velocity, acceleration, and time.
- Commonly used equations include: v = u + at, s = ut + 0.5at², and v² = u² + 2as.
- Terminal Velocity:
- It is the constant speed that a freely falling object eventually reaches when the resistance of the medium prevents further acceleration.
- For objects falling through air, terminal velocity depends on the object's size, shape, and mass.
Last updated on Jun 30, 2025
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