Which two numbers should be interchanged to make the given equation correct?

69 + 15 − (14 × 4 ) ÷ 2 + (48 ÷ 3) = 58

(NOTE: Numbers must be interchanged and not the constituent digits e.g. if 2 and 3 are to be interchanged in the equation 43 × 3 + 4 ÷ 2, then interchanged equation is 43 × 2 + 4 ÷ 3)

Question

Question

This question was previously asked in

SSC CHSL Exam 2024 Tier-I Official Paper (Held On: 05 Jul, 2024 Shift 1)

Answer 1

BODMAS

Given : 69 + 15 − (14 × 4 ) ÷ 2 + (48 ÷ 3) = 58

Option 1) 4 and 2

69 + 15 − (14 × 4 ) ÷ 2 + (48 ÷ 3) = 58 ⇒ 69 + 15 − (14 × 2 ) ÷ 4 + (48 ÷ 3) = 58

⇒ 69 + 15 − (14 × 2 ) ÷ 4 + (48 ÷ 3) = 58

⇒ 69 + 15 − 28 ÷ 4 + 16 = 58

⇒ 69 + 15 + 16 − 7 = 58

⇒ 100 - 7 = 58

⇒ 93 ≠ 58 (LHS ≠ RHS)

Option 2) 48 and 15

69 + 15 − (14 × 4 ) ÷ 2 + (48 ÷ 3) = 58 ⇒ 69 + 48 − (14 × 4 ) ÷ 2 + (15 ÷ 3) = 58

⇒ 69 + 48 − (14 × 4 ) ÷ 2 + (15 ÷ 3) = 58

⇒ 69 + 48 − 56 ÷ 2 + 5 = 58

⇒ 69 + 48 + 5 − 28 = 58

⇒ 122 - 28 = 58

⇒ 94 ≠ 58 (LHS ≠ RHS)

Option 3) 69 and 48

69 + 15 − (14 × 4 ) ÷ 2 + (48 ÷ 3) = 58 ⇒ 48 + 15 − (14 × 4 ) ÷ 2 + (69 ÷ 3) = 58

⇒ 48 + 15 − (14 × 4 ) ÷ 2 + (69 ÷ 3) = 58

⇒ 48 + 15 − 56 ÷ 2 + 23 = 58

⇒ 48 + 15 + 23 − 28 = 58

⇒ 86 - 28 = 58

⇒ 58 = 58 (LHS = RHS)

Option 4) 3 and 4

69 + 15 − (14 × 4 ) ÷ 2 + (48 ÷ 3) = 58 ⇒ 69 + 15 − (14 × 3 ) ÷ 2 + (48 ÷ 4) = 58

⇒ 69 + 15 − (14 × 3 ) ÷ 2 + (48 ÷ 4) = 58

⇒ 69 + 15 − 42 ÷ 2 + 12 = 58

⇒ 69 + 15 + 12 − 21 = 58

⇒ 96 - 12 = 58

⇒ 84 ≠ 58 (LHS ≠ RHS)

Hence, "Option 3" is the correct answer.