Puzzle MCQ Quiz - Objective Question with Answer for Puzzle - Download Free PDF

1. Charan is assigned to Neutrogena, but not with Simran or Pranav.  

2. Simran is assigned to a brand that is neither Neutrogena nor Cetaphil. 

3. Fatima and Simran are on the same team.

4. Meher works with Dev, but their brand is not The Body Shop. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

5. Jai works with only one other person, and not with the Neutrogena brand.

Now, we can eliminate Case 1.

6. Lavanya does not work with Simran or Meher.

7. Fatima and Meher are associated with different brands. 

8. Pranav does not work with Dev or Jai. 

9. Tanya is not associated with Neutrogena.  

This is our final arrangement,

I. Lavanya and Simran are in the same skincare brand: False

II. Meher works with Dev: True

III. Tanya is not associated with Cetaphil: True

Hence, the correct answer is Only I.

1. Charan is assigned to Neutrogena, but not with Simran or Pranav.  

2. Simran is assigned to a brand that is neither Neutrogena nor Cetaphil. 

3. Fatima and Simran are on the same team.

4. Meher works with Dev, but their brand is not The Body Shop. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

5. Jai works with only one other person, and not with the Neutrogena brand.

Now, we can eliminate Case 1.

6. Lavanya does not work with Simran or Meher.

7. Fatima and Meher are associated with different brands. 

8. Pranav does not work with Dev or Jai. 

9. Tanya is not associated with Neutrogena.  

This is our final arrangement,

Hence, the correct answer is Simran.

1. Charan is assigned to Neutrogena, but not with Simran or Pranav.  

2. Simran is assigned to a brand that is neither Neutrogena nor Cetaphil. 

3. Fatima and Simran are on the same team.

4. Meher works with Dev, but their brand is not The Body Shop. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

5. Jai works with only one other person, and not with the Neutrogena brand.

Now, we can eliminate Case 1.

6. Lavanya does not work with Simran or Meher.

7. Fatima and Meher are associated with different brands. 

8. Pranav does not work with Dev or Jai. 

9. Tanya is not associated with Neutrogena.  

This is our final arrangement,

Except for Jai, all others belong to the same group.

Hence, the correct answer is Jai.

1. Charan is assigned to Neutrogena, but not with Simran or Pranav.  

2. Simran is assigned to a brand that is neither Neutrogena nor Cetaphil. 

3. Fatima and Simran are on the same team.

4. Meher works with Dev, but their brand is not The Body Shop. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

5. Jai works with only one other person, and not with the Neutrogena brand.

Now, we can eliminate Case 1.

6. Lavanya does not work with Simran or Meher.

7. Fatima and Meher are associated with different brands. 

8. Pranav does not work with Dev or Jai. 

9. Tanya is not associated with Neutrogena.  

This is our final arrangement,

Hence, the correct answer is Three.

1. Charan is assigned to Neutrogena, but not with Simran or Pranav.  

2. Simran is assigned to a brand that is neither Neutrogena nor Cetaphil. 

3. Fatima and Simran are on the same team.

4. Meher works with Dev, but their brand is not The Body Shop. 

Here, we have 2 Cases, i.e., Case 1 and Case 2.

5. Jai works with only one other person, and not with the Neutrogena brand.

Now, we can eliminate Case 1.

6. Lavanya does not work with Simran or Meher.

7. Fatima and Meher are associated with different brands. 

8. Pranav does not work with Dev or Jai. 

9. Tanya is not associated with Neutrogena.  

This is our final arrangement,

I. Jai works with Lavanya. : True

II. Dev and Lavanya are in different skincare brands. : True

III. Fatima and Jai are working together. : False

Hence, the correct answer is Only I and II are true.

Let my current age = x years and my cousin’s age = y years.

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

⇒ 3x/5 = 5y/6

⇒ 18x = 25y

My age ten years ago will be his age four years hence,

⇒ x – 10 = y + 4

⇒ y = x – 14,

⇒ 18x = 25(x – 14)

⇒ 18x = 25x – 350

⇒ 7x = 350

Let,

Price of one pen = x

Price of one notebook = y

Given:

1) Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180

=> 3x + 6y = 180

=> 3x = 180 – 6y

=> x = (180 – 6y) ÷ 3

=> x = 60 – 2y --------------- (i)

2) Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116

=> 5x + 2y = 116

Putting the value of x from eq (i)

=> 5(60 – 2y) + 2y = 116

=> 300 – 10y + 2y = 116

=> 300 – 116 = 10y – 2y

=> 8y = 184

=> y = 23

Mohit spend on buying 6 notebooks

=> 6y = 6 × 23 = 138

According to the question, after interchanging the given two signs and two numbers i.e :

• × and +
• Two numbers 3 and 9

So,

I. 7 + 3 – 8 ÷ 2 × 9

⇒ 7 + 3 - 4 × 9

⇒ 7 + 3 - 36

⇒ 10 - 36

⇒ -26

II. 4 + 3 – 9 × 8 ÷ 2

⇒ 4 + 3 - 9 × 4

⇒ 4 + 3 - 36

⇒ 7 - 36

⇒ -29

Let the age of father be F and that of son be S.

F + S = 50 (Given)

S = 50 – F     _____ (i)

Six years back father's age was 6 more than thrice his son's age.

According to problem:

(F – 6) = 3(S – 6) + 6     _____ (ii)

Substituting the value of equation (i) in (ii), we get:

F – 6 = 3(50 – F – 6) + 6

⇒ F – 6 = 3(44 – F) + 6

⇒ F – 6 = 132 – 3F + 6

⇒ F + 3F = 132 + 6 + 6

⇒ 4F = 144

⇒ F = 144/4

⇒ F = 36

So, father's age 6 years hence = (36 + 6) = 42

Hence, ‘42’ is the correct answer.

The logic followed here is:

1) 15 → 12 + 3 = 15 kg

2) 20 → 12 + 8 = 20 kg

3) 23 → 12 + 8 + 3 = 23 kg

4) 21 → It CANNOT be the total weight, in kg, of any combination of these boxes.

Let the number of bulls be ‘a’ and the number of hens be ‘b’.

So, the total numbers of heads are (a + b) and total numbers of legs are (4a + 2b).

According to question:

(4a + 2b) = 2(a + b) + 48

4a + 2b = 2a + 2b + 48

4a + 2b – 2a – 2b = 48

2a = 48

a = 24

So, the number of bulls is 24.

Hence, ‘24’ is the correct answer.

Given:

A side of a square-shaped park is 12 m.

• If a square-shaped garden with a side of 24 m is developed around the park, then the garden with the park will look like the picture below:

Formula:

Area of square = Side × Side

Calculation:

=> Total area of the park including the garden = Area of the outer square = 24 × 24

=> Area of square = 576 m2

Let the present age of Anamika be A, Malini be M and that of Srinidhi be S.

The, according to the question:

1) Seven years from now, Anamika will be as old as Malini was 4 years ago. 

A + 7 = M - 4

⇒ M = A + 11

S = 2 years

And, 

2) Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years.

\({(A + 10 + M + 10 + S + 10) \over 3} = 33 \)

\(A + M + S + 30 = 33 \times 3\)

A + M + S = 99 - 30

A + M + S = 69 

Now, by substituting the above values,

A + (A + 11) + 2 = 69 

2A + 13 = 69

A = 56 ÷ 2

A = 28 years

Hence, the present age of Anamika is 28 years is the correct answer.

For this question, We have to check the given equation as-

146 –  2 + 3 × 123 × 5 + 2

New equation after replacing symbols-

146 ÷ 2 × 3 – 123 - 5 × 2

According to the BODMAS rule-

⇒ 73 × 3 –  123 – 5 × 2

⇒ 219 –  123 –  10

⇒ 86

Hence, Option (4) is correct.

BODMAS Table: 

Given equation I: 55 + 42 – 36 × 20 ÷ 9 = 17

Now, if '20 and 36' are interchanged, then:

⇒ 55 + 42 – 20 × 36 ÷ 9 = 17

⇒ 55 + 42 – 20 × 4 = 17

⇒ 55 + 42 – 80 = 17

⇒ 97 – 80 = 17

= 17 = 17.

LHS = RHS.

Given equation II: 20 ÷ 2 × 36 + 81 – 41 = 400

Now, if '20 and 36' are interchanged, then:

⇒ 36 ÷ 2 × 20 + 81 – 41 = 400

⇒ 18 × 20 + 81 – 41 = 400

⇒ 360 + 81 – 41 = 400

⇒ 441 – 41 = 400

= 400 = 400

LHS = RHS.

Here, Both I and II are correct equation after interchanging the given symbol.

Hence, the correct answer is "Option 3".