Question
Download Solution PDFWhat will be the value of the maximum absolute shear stress produced in a thin cylinder if hoop stress = 40 MPa and longitudinal stress = 20 MPa?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In a thin-walled cylinder under internal pressure, two principal stresses act on the wall: hoop stress and longitudinal stress.
Given:
- Hoop stress, σh = 40 MPa
- Longitudinal stress, σl = 20 MPa
- Radial stress = 0 MPa (negligible in thin cylinders)
Formula for Maximum Absolute Shear Stress:
\(\tau_{\text{max}} = \frac{1}{2}(σ_{\text{max}} - σ_{\text{min}})\)
Calculation:
\(\tau_{\text{max}} = \frac{1}{2}(40 - 0) = 20~\text{MPa}\)
Last updated on Jun 7, 2025
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