Two walls of equal height are on either side of a road, which is 100 m wide. At a point on the road two stairs are along the two walls in such a way that they indicate the two angles of elevation from that point at 60° and 30°. The length of the longer stair is:

Question

Question

This question was previously asked in

NTPC CBT-I (Held On: 5 Jan 2021 Shift 2)

Answer 1

F1 Arun Madhuri 26.10.2021 D9

Given:

Distance between two walls = 100 m

Concept:

The longer stair will be AC as the corresponding side making the smaller angle is larger than that of making bigger angle.

Calculation:

Let the height of each of the walls = h

BC + CE = BE = 100

⇒ CE = 100 - BC .......(1)

In triangle ABC, AB/BC = tan 30°

⇒ h/BC = 1/√3

⇒ BC = √3h.......(2)

In triangle CDE, DE/CE = tan 60°

⇒ h/(100 - BC) = √3

h/(100 - √3h) = √3

h = 100√3 - 3h

4h = 100√3

h = 25√3 m ...... (3)

By (2) and (3)

BC = √3h = √3 × 25√3

⇒ BC = 75 m

Again in triangle ABC, BC/AC = cos 30°

⇒ 75/AC = √3/2

⇒ 150 = √3 × AC

⇒ AC = 150/√3

⇒ AC = 150/√3 ×√3/√3

∴ AC = 50√3 m

Alternate MethodBy Ratio Method

F1 Arun Madhuri 26.10.2021 D10

3 + 1 = 4 = 100 m

\(\Rightarrow 2√{3}= \frac{100}{4}\times 2√{3}\)

AC = 50√3