Question
Download Solution PDFThree identical coils connected in delta to a 415 V, 3-phase supply take a total power of 50 kW and line currents of 70 A. Determine the total kVA taken by the coils.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
In 3ϕ delta connected system, the apparent power is given by:
\(S=3V_pI_p\)
where, Vp = Phase Voltage
Ip = Phase Current
Calculation
Given, Vp = 415 V
IL = 70 A
\(I_p={70\over \sqrt{3}}\)
\(S=3\times 415\times {70\over \sqrt{3}}\)
S = 50.32 kVA
Last updated on Jun 16, 2025
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