The value of k so that following is probability mass function

X: -2 -1 0 1 2 3
P(X = x): 2k 3k 4k 3k 2k k

is

This question was previously asked in
SSC CGL Tier-II ( JSO ) 2021 Official Paper ( Held On: 10 August 2022 )
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  1. \(\frac{2}{15}\)
  2. \(\frac{1}{14}\)
  3. \(\frac{1}{16}\)
  4. \(\frac{1}{15}\)

Answer (Detailed Solution Below)

Option 4 : \(\frac{1}{15}\)
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Detailed Solution

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The correct answer is 1/15

Key Points

  • The sum of all the probabilities is always equal to 1.
  • For a discrete random variable X with a probability mass function, the probabilities must sum to 1, which is a requirement for a valid probability distribution. 
    • Hence, the value of k can be determined by setting the sum of all the probabilities equal to 1 and solving for k.
  • In this case, the sum of all the probabilities is given by
    • Hence,\( 2k + 3k + 4k + 3k + 2k + k = 1\)
    • ⇒ 15k = 1
    • \( k = 1/15\)
  • A probability mass function is a function that assigns a probability to each value of a discrete random variable.
  • The probabilities assigned to the values of a discrete random variable must sum to 1.
  • The value of k can be determined by solving for the sum of all the probabilities equal to 1.

 Additional Information

  • Once the value of k is determined, the probabilities can be found by multiplying each probability by k. In this case, the probabilities are
  • P(X = -2) = 2k = 2/15 
    P(X = -1) = 3k = 3/15 
    P(X = 0) = 4k = 4/15 
    P(X = 1) = 3k = 3/15 
    P(X = 2) = 2k = 2/15 
    P(X = 3) = k = 1/15
  • A probability mass function must be a valid probability distribution, meaning that all probabilities must be non-negative and the sum of all probabilities must be equal to 1.
  • The value of k can be determined by solving for the sum of all the probabilities equal to 1.
  • The probabilities assigned to the values of a discrete random variable provide information about the likelihood of each value of X.
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