Question
Download Solution PDFThe source impedance is ZS = (9 + j6) Ω in the circuit shown below. The maximum real power is transferred to the load impedance (ZL) when ZL is equal to:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFMaximum power transfer theorem
Case 1: For AC circuit
In the case of AC voltage sources, maximum power flows from the source to load only if the load impedance’s value is equivalent to the complex conjugate of the thevenin's impedance.
\(Z_L=Z_{s}^{*}\)
Case 2: For the DC circuit
In the case of DC voltage sources, maximum power flows from the source to load if the resistance of the given load must be equal to the thevenin's resistance.
\(R_L=R_{s}\)
Calculation
Given, Zs = 9 + j6
The value of load impedance is given by:
\(Z_L=Z_{s}^{*}=({9+j6})^{*}\)
During conjugate operation, the sign of the imaginary part changes.
\(Z_L={9-j6}\)
Last updated on May 29, 2025
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