Question
Download Solution PDFWhat is the value of resistance RL in the circuit shown in the figure to deliver maximum power from the source to load?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
From the above circuit, 10 || 30 & 20 || 40 Ω
\(R_T=\frac{10\times 30}{10+30} + \frac{20\times40}{20+40}\)
\(R_T=\frac{300}{40} + \frac{800}{60}\)
⇒ 7.5 + 13.33 = 20.83 Ω
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