Question
Download Solution PDFఒకవేళ a + b + c = 6 మరియు a2 + b2 + c2 = 14అయితే, (a - b)2 + (b - c)2 + (c - a)2 విలువ ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చింది:
a + b + c = 6 మరియు a2 + b2 + c2 = 14,
గణన:
a = 1 , b = 2 మరియు c = 3 అనుకోని ప్రతిక్షేపించాలి
a + b + c = 1 + 2 + 3 = 6
కాబట్టి విలువ
(a - b)2 + (b - c)2 + (c - a)2 .
⇒ (1 - 2)2 + (2 - 3)2 + (3- 1)2 .
⇒ 1 + 1 + 4 = 6
∴ సరైన ఎంపిక 4
Last updated on Jul 9, 2025
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