Question
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\(\rm \frac{{\cos (\pi - A).\cot \left( {\frac{\pi }{2} + A} \right)\cos ( - A)}}{{\tan (\pi + A)\tan \left( {\frac{{3\pi }}{2} + A} \right)\sin (2\pi - A)}}\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFवापरलेली संकल्पना:
वापरलेले सूत्र:
- cos (π - θ) = - cos θ
- cot (90 + θ) = - tan θ
- cos (-θ) = cos θ
- tan (π + θ) = tan θ
- tan (3π/2 + θ) = - cot θ
- sin (2π - θ) = - sin θ
गणना:
\(\rm \frac{{\cos (π - A).\cot \left( {\frac{π }{2} + A} \right)\cos ( - A)}}{{\tan (π + A)\tan \left( {\frac{{3π }}{2} + A} \right)\sin (2π - A)}}\)
वरील सूत्र वापरून
\(\rm \frac{{\ (-cos A)\ . \ ( {-tan A} )\ \ .\ cos A}}{{\tan A\ .\ (-cot A ).\ (-sin A)}}\)
⇒ \(\frac{cos A\ .\ cos A}{cot A\ . \ sin A}\)
परंतु, cos θ / sin θ = cot θ
⇒ - cot A. cos A/ cot A
⇒ cos A
∴ योग्य उत्तर cos A आहे.
Last updated on Jul 17, 2025
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