Question
Download Solution PDFदोन सलग संख्यांचा गुणाकार शोधा, ज्यात पहिली संख्या चार पटीने, दूसर्या संख्येच्या तीन पटीपेक्षा 10 ने अधिक आहे.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिल्याप्रमाणे :
पहिली संख्या चार पटीने, दूसर्या संख्येच्या तीन पटीपेक्षा 10 ने अधिक आहे..
गणना:
समजा त्या संख्या ‘a’ आणि ‘a + 1’.
प्रश्नानूसार :
4a = 3 × (a + 1) + 10
⇒ a = 13
म्हणूनच, त्या संख्या 13 आणि 14 आहे
∴गुणाकार= 13 × 14 = 182Last updated on Jun 27, 2025
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