\(\rm \frac{sin\space23°}{cos\space67°}+\frac{cos\space71°}{sin\space19°}\) ഇതിന്റെ മൂല്യം ഇതാണ്:

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Answer (Detailed Solution Below)

Option 3 : 2
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നൽകിയിരിക്കുന്നത്:

\(\rm \frac{sin\space23°}{cos\space67°}+\frac{cos\space71°}{sin\space19°}\)

ഉപയോഗിച്ച സൂത്രവാക്യം:

sin (90°- x) = cos x 

cos (90°- x) = sin x 

കണക്കുകൂട്ടൽ:

\(\rm \frac{sin\space23°}{cos\space67°}+\frac{cos\space71°}{sin\space19°}\)

⇒ sin(90° - 67°)/cos 67° + cos (90° - 19°)/sin 19°

⇒ cos 67°/ cos 67° + sin 19°/sin 19°

⇒ 1 + 1 = 2 

∴ ആവശ്യമായ ഫലം = 2

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