Let ΔABC ∼ Δ PQR and ar(∆ABC)/ar(∆PQR) =4/25. If AB = 12 cm, BC = 8 cm and AC = 9 cm, then QR is equal to:

This question was previously asked in
SSC CHSL Previous Paper 20 (Held On: 8 Jul 2019 Shift 3)
View all SSC CHSL Papers >
  1. 20
  2. 15
  3. 17.5
  4. 18

Answer (Detailed Solution Below)

Option 1 : 20
Free
SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 02 Aug 2023 Shift 1)
2.6 Lakh Users
100 Questions 200 Marks 60 Mins

Detailed Solution

Download Solution PDF

F4 S.G Deepak 11.12.2019 D 4

ΔABC ∼ ΔPQR

∴ (BC/QR)2 = ar(∆ABC)/ar(∆PQR)

⇒ (8/QR)2 = 4/25

⇒ 8/QR = 2/5

∴ QR = 20 cm

Note∶ The question was incorrect in the official paper. It has been corrected and updated it accordingly.

Latest SSC CHSL Updates

Last updated on May 28, 2025

-> The SSC has released the SSC CHSL exam calendar for various exams including CHSL 2025 Recruitment. As per the calendar, SSC CHSL Application process will be active from 23rd June 2025 to 18th July 2025. 

-> The Exam Date for the SSC CHSL 2025 will be from 8th September 2025 to 18th September, 2025. 

-> The SSC CHSL is conducted to recruit candidates for various posts such as Postal Assistant, Lower Divisional Clerks, Court Clerk, Sorting Assistants, Data Entry Operators, etc. under the Central Government. 

-> The SSC CHSL Selection Process consists of a Computer Based Exam (Tier I & Tier II).

-> To enhance your preparation for the exam, practice important questions from SSC CHSL Previous Year Papers. Also, attempt SSC CHSL Mock Test.  

More Triangles, Congruence and Similarity Questions

Get Free Access Now
Hot Links: teen patti master plus teen patti classic dhani teen patti