If sum and product of the roots of a quadratic equation are (4 - 3√2) and -28 respectively, then find the quadratic equation.

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RRB NTPC Graduate Level CBT-I Official Paper (Held On: 05 Jun, 2025 Shift 3)
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  1. x2 - ( 4 - 3√2​) x - 28 = 0
  2. x2 + (4 + 3√2​) x + 28 = 0
  3. x2 - (4 + 3√2​) x + 28 = 0
  4. x2 + (4 - 3√2) x - 28 = 0

Answer (Detailed Solution Below)

Option 1 : x2 - ( 4 - 3√2​) x - 28 = 0
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Detailed Solution

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Given:

Sum of roots = 4 - 3√(2)

Product of roots = -28

Formula Used:

The quadratic equation based on sum (S) and product (P) of roots is:

x2 - (Sum of roots) × x + Product of roots = 0

Calculation:

Substitute the values of Sum of roots = 4 - 3√(2) and Product of roots = 28 :

⇒ x2 - (4 - 3√2) × x + (-28) = 0

⇒ x2 - (4x - 3√2x) - 28 = 0

The quadratic equation is x2 - (4 - 3√2)x - 28 = 0.

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