If N + \(1\over N\) = √3, then find the value of N6 + \(1\over N^6\) + 11.

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SSC CHSL Tier-I Exam 2022 Official Paper (Held On: 15 March, 2023 Shift 1)
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  1. -11
  2. -2
  3. 11
  4. 9

Answer (Detailed Solution Below)

Option 4 : 9
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Detailed Solution

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Given:

N + 1/N = √3

Formula:

If x + 1/x = a, then x3 + 1/x3 = a3 - 3a

Calculation:

N3 + 1/N= (√3)3 - 3 × √3

⇒ N3 + 1/N= 0

Now square both sides

(N3 + 1/N3)2= 0

N6 + 1/N6 + 2 = 0

N6 + 1/N6  = -2

Add 11 on both sides:

N6 + 1/N6 + 11 = -2 + 11

N6 + 1/N6 + 11 = 9

∴ The required answer = 9

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