If ∆ ABC ~ ∆DEF such that 2AB = DE and BC = 8 cm, then the length of EF is:

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 07 Dec 2022 Shift 2)

Answer 1

Given:

∆ ABC ~ ∆DEF

2AB = DE

BC = 8 cm

Concept used:

The ratio of the corresponding side of the similar triangle is equal

Calculations:

As, ∆ ABC ~ ∆DEF

⇒ \(\frac{AB}{DE}=\frac{BC}{EF}\)

As we know, 2AB = DE

⇒ \(\frac{AB}{2AB}=\frac{8}{EF}\)

⇒ EF = 8 \(\times\) 2 = 16 cm

⇒ Hence, The value of EF is 16 cm.