एक ठेकेदार को प्लंबिंग का ठेका मिलने की प्रायिकता 2 / 3 है और उसे बिजली का ठेका नहीं मिलने की प्रायिकता 5 / 9 है। यदि कम से कम एक ठेका मिलने की प्रायिकता 4 / 5 है, तो उसे दोनों ठेके मिलने की प्रायिकता है:

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SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )
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  1. 13 / 45
  2. 14 / 45
  3. 16 / 45
  4. 17 / 45

Answer (Detailed Solution Below)

Option 2 : 14 / 45
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दिया गया है

प्लंबिंग का ठेका मिलने की प्रायिकता = P(A) = 2/3

बिजली का ठेका नहीं मिलने की प्रायिकता P(B̅) = 5/9

कम से कम एक ठेका मिलने की प्रायिकता P(A U B) = 4/5

गणना

बिजली का ठेका मिलने की प्रायिकता = 1 - P(B̅)

⇒ = 1- 5/9 = 4/9

दोनों ठेके मिलने की प्रायिकता P(A ∩ B) = P(A) + P(B) - P(A U B)

⇒ P(A ∩ B) = 2/3 + 4/9 - 4/5

⇒ (90 + 60 - 108)/135

उसे दोनों ठेके P(A ∩ B) मिलने की प्रायिकता 14/45 है।

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