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10 + 8 + 6 - 48 ÷ (4 x 6)

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RRB Technician Grade III Official Paper (Held On: 30 Dec, 2024 Shift 3)
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  1. 12
  2. 26
  3. 22
  4. -1

Answer (Detailed Solution Below)

Option 3 : 22
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दिया गया है:

10 + 8 + 6 - 48 ÷ (4 x 6)

प्रयुक्त सूत्र:

संक्रियाओं का क्रम (BODMAS/BIDMAS): कोष्ठक, घात (अर्थात घात और वर्गमूल, आदि), भाग और गुणा, योग और घटाव;

गणना:

10 + 8 + 6 - 48 ÷ (4 × 6)

⇒ 24 - 48 ÷ 24

⇒ 24 - 2 = 22

∴ सही उत्तर विकल्प 3 है।

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