Question
Download Solution PDFयदि एक प्रतियोगिता में दो न्यायाधीशों द्वारा छह हस्तलेखनों को क्रमांकित किया गया है और क्रमांक इस प्रकार है:
| हस्त लेखन | ||||||
| 1 | 2 | 3 | 4 | 5 | 6 | |
| न्यायाधीश 1 | 6 | 5 | 4 | 3 | 2 | 1 |
| न्यायाधीश 2 | 1 | 2 | 3 | 4 | 5 | 6 |
तो स्पीयरमैन के क्रमांक सहसंबंध गुणांक का मान है
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसूत्र
स्पीयरमैन का क्रमांक सहसंबंध गुणांक = r = 1 -(6∑d2)/n(n2 - 1)
गणना
|
न्यायाधीश 1(R1) |
न्यायाधीश 2(R2) |
(R1 – R2) = D |
D2 |
|
6 |
1 |
5 |
25 |
|
5 |
2 |
3 |
9 |
|
4 |
3 |
1 |
1 |
|
3 |
4 |
-1 |
1 |
|
2 |
5 |
-3 |
9 |
|
1 |
6 |
-5 |
25 |
|
कुल |
|
|
∑ D2 = 70 |
सूत्र के अनुसार
⇒ r = 1 - [(6 × 70)/6(62 - 1)]
⇒ r = 1 - [(6 × 70/210]
⇒ r = 1 - 6/3
∴ स्पीयरमैन क्रमांक सहसंबंध गुणांक - 1 है।
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