यदि समीकरण 2x2 - 3x - 5 = 0 के मूल α और β हैं, तब निम्नलिखित में से किस समीकरण के मूल  और  हैं?

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RRB Group D 26 Sept 2022 Shift 2 Official Paper
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  1. 10x2 - 29x + 10 = 0
  2. 10x2 + 29x + 10 = 0
  3. 10x2 + 29x - 10 = 0
  4. 10x2 - 29x - 10 = 0

Answer (Detailed Solution Below)

Option 2 : 10x2 + 29x + 10 = 0
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RRB Group D Full Test 1
100 Qs. 100 Marks 90 Mins

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दिया गया:

समीकरण 2x 2 - 3x - 5 = 0 के मूल α और β हैं।

एक अन्य समीकरण के मूल और हैं।

गणना:

दिए गए समीकरण पर हिट और ट्रायल विधि का उपयोग करके α और β के मान ज्ञात करें।

2x 2 - 3x - 5 = 0

= 2x 2 - 5x + 2x - 5

= x(2x - 5) +1(2x - 5)

= (2x - 5)(x + 1)

x = और x = -1

इस प्रकार α = और β = -1

अब और को हल करने पर, हमें प्राप्त होता है

=

=

अब,

द्विघात समीकरण जिसके मूल और हैं:

(x - ()) (x - ()) = 0

⇒ (x + 5/2) (x + 2/5) = 0

⇒ x2 + 5x/2 + 2x/5 + 1 = 0

⇒ (10x2 + 25x + 4x + 10)/10 = 0

⇒ 10x2 + 29x + 10 = 0

∴ सही उत्तर विकल्प (2) है

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