अनुमानित, दिए गए आंकड़ों के लिए भिन्नता का गुणांक जहां पियरसन का दूसरा विषमता का माप = 0.42, अंकगणितीय माध्य = 86 और माध्यिका = 80 है:

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SSC CGL JSO Tier-II, 2018 (Statistics) Official Paper-III (Held On: 14 Sept, 2019)
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  1. 53
  2. 51
  3. 50
  4. 52

Answer (Detailed Solution Below)

Option 3 : 50
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Detailed Solution

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दिया गया है

पियरसन का विषमता का माप = 0.42

माध्य = x̅ = 86

माध्यिका = Md = 80

सूत्र

विषमता = Skp = 3(माध्य – माध्यिका)/मानक विचलन 

गणना

0.42 = 3(x̅  - Md)/σ

⇒ 0.42 = 3(86 – 80)/σ

⇒ σ = 18/0.42

⇒ σ = 300/7

भिन्नता का गुणांक = मानक विचलन/माध्य = (σ/x̅) × 100

⇒ CV = (300/7/86) × 100

⇒ (300/7 × 86) × 100

∴ भिन्नता का गुणांक 50 है 

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