Question
Download Solution PDF300Ω प्रतिरोध का एक हीटर 10 मिनट के लिए मुख्य आपूर्ति से जुड़ा है। यदि इस दौरान हीटर में उत्पन्न ऊष्मा 18 J है, तो इसके माध्यम से धारा ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना
हीटर द्वारा उत्पन्न ऊष्मा निम्न द्वारा दी जाती है\:
\(H=i^2Rt\)
जहाँ, i = धारा
R = प्रतिरोध
t = समय
गणना
दिया गया है, R = 300 Ω
t = 10 min = 600 sec
H = 18 J
\(18=i^2(300)(600)\)
i = 0.01 A
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