एक अलमारी में 8 जोड़ी जूते हैं। यदि यादृच्छिक रूप से 4 जूतों का चयन किया जाता है, तो सभी चार जूते एक ही प्रकार (बायें या दायें) के होने की प्रायिकता है:

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गणना

जूतों की कुल संख्या = 16

8 बायें पैर के और 8 दायें पैर के हैं।

जब हम यादृच्छिक रूप से 4 जूतों का चयन करते हैं।

जूते चुनने के तरीकों की कुल संख्या = 16c4

यदि चयन किये गए जूते सभी दायें पैर के या बायें पैर के हैं तो प्रायिकता = 2 × 8c4/16c4

⇒ [2 × 8!/4! × 4!]/16!/4! × 12!]

⇒ [2 × 8!/4! × 4!]/12! × 4!/16!]

⇒ 2 × 8! × 12!/4! × 16!]

⇒ (2 × 8 × 7 × 6 × 5 × 4! × 12!)/(4! × 16 × 15 × 14 × 13 × 12!)

∴ अपेक्षित प्रायिकता 1/13 है।

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